How many ways are there to put the balls into the boxes?

How many ways are there to put the balls into the boxes?

How many ways are there to place the balls into the boxes? There are only six ways.

How many ways can you distribute 4 balls into 5 boxes?

If there was no restriction; the distribution of 4 distinguishable balls among 5 boxes could have been done in (5 * 5 * 5 * 5) ways = 625 ways.

How many ways 5 balls can be placed in 3 boxes such that no box remains empty?

* Now you have ensured that no box remains empty. * Now, every ball can be placed in boxes in three different ways. Hence, the total no. of ways of placing the rest 5 balls is 3*3*3*3*3=243.

How many ways can group N objects in K box?

So the answer is 9. Distributing n indistinguishable objects into k indistinguishable boxes is the same as writing n as a sum of at most k positive integers in non-increasing order. There is no simple closed formula for this number.

How many ways can n balls be put into 5 boxes if no box has exactly 2 balls?

Total ways of putting 5 balls in five distinct boxes = (5^5) = 3125. Ways of choosing two empty distinct boxes = 5×4= 20. Next, ways of putting one ball each in 3 remaining boxes = 3×2×1=6. Ways to put remaining 2 balls in any of above 3 boxes = 3×3=9.

How many ways can you put 3 balls in 4 boxes?

Each ball can be put into any one of the 3 boxes, independently of where the other balls are. There are 3*3*3*3 = 81 ways of doing this.

How many ways can we pick any number of balls from a pack of 3 different balls?

Now, you can easily calculate the no. of ways to choose 3 balls as follows: 28+21+15+10+6+3+1= 84.

How many ways to distribute 5 balls into 3 boxes if each box must have at least one ball in it if?

We have to distribute 5 distinct balls into 3 identical boxes. Thus, n = 5 and k = 3. Therefore, there are a total of 41 possibilities.

What is the number of ways in which you can distribute 5 balls in 3 boxes when?

As there are 5 balls and three boxes each ball has 3 choices. So to answer is 3x3x3x3x3=243.

How many ways are there of distributing n identical balls among K boxes?

If we are supposed to distribute k distinct objects to n identical recipients so that each gets at most one, we cannot do so if k>n, so there are 0 ways to do so. On the other hand, if k≤n, then it doesn’t matter which recipient gets which object, so there is only one way to do so.

How many ways can group N items be?

The total number of ways that the parts can be selected is 4×3×5×4 or 240 ways. Factorial Notation: the notation n! (read as, n factorial) means by definition the product: n!

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