## What is the vector equation of YZ plane?

The xy-plane contains the x- and y-axes and its equation is z = 0, the xz-plane contains the x- and z-axes and its equation is y = 0, The yz-plane contains the y- and z-axes and its equation is x = 0.

## What is the normal vector of YZ plane?

(1, 0, 0)
It is said that a plane is perpendicular to the yz-plane, then the plane will be parallel to the x-axis. If the planes are perpendicular, then their normals are also perpendicular. Thus the normal vector, can be said as (1, 0, 0), as the normal of the x-axis, parallel to plane and yz are perpendicular.

What is the equation of a plane in the XY-plane?

The (cartesian) equation of a plane is linear in the coordinates x and y, that is, of the form ax+by+cz+d=0. The normal direction to this plane is (a,b,c). The intersection of this plane with the x-axis, or x-intercept, is x=-d/a; the y-intercept is y=-d/b, and the z-intercept is z=-d/c.

### What is the XY-plane vector?

The plane containing the x– and y-axes is called the xy-plane. The plane containing the x– and z-axes is called the xz-plane, and the y– and z-axes define the yz-plane. Points that lie in octants have three nonzero coordinates.

### What are the direction ratios of XY-plane?

. Direction Ratios. If a, b, c are three numbers proportional to the direction cosine l, m, n of a straight line, then a, b, c are called its direction ratios. They are also called direction numbers or direction components.

How do you find the equation of a plane given two points?

First take a direction vector to those two points, then, take the given normal from the equation of a plane. The cross product of the direction vector with the normal will then gives the normal of the desired plane, finally take either of the two point and form a point normal equation of a plane.

## What is the YZ plane?

y-z Plane. The plane formed by the y-axis and the z-axis. See also. x-y plane, x-z plane.

## How do you find the equation of the plane parallel to the YZ plane?

Solution : Any plane parallel to YZ-plane, is x=k. Sinece, it passes through `(-3,2,0)`, we have `-3=k`. Hence, the required equation of the plane is `x=-3`.

What is the XY plane vector?